Understanding Regrouping with Blocks: Solving 43 + 8

In math, adding numbers can be tricky, especially when we deal with numbers like 43 + 8. One way to make it easier is by using blocks! Let’s break down how we can solve this using blocks and regrouping.

What We Have:

We are adding 43 + 8.

43 has 4 tens and 3 ones.
8 has 8 ones.

Step 1: Start with the Blocks for 43

To represent 43 with blocks, we use:

4 ten blocks (each block representing 10)
3 one blocks (each block representing 1)

Here’s what it looks like:

    [🟩][🟩][🟩][🟩]  (4 tens = 40)
    [🟦][🟦][🟦]      (3 ones = 3)

Step 2: Add the 8 Ones

Now, we add 8 ones to the 43. We place 8 one blocks next to the 3 ones:

    [🟩][🟩][🟩][🟩]  (4 tens = 40)
    [🟦][🟦][🟦][🟦][🟦][🟦][🟦][🟦]  (8 ones)

When we combine the 3 ones and the 8 ones, we get 11 ones in total.

Step 3: Regroup the Ones

Since 10 ones make a full ten, we can regroup the 11 ones. We take 10 of the ones and turn them into 1 ten block.

This is what it looks like after regrouping:

    [🟩][🟩][🟩][🟩][🟩]  (5 tens = 50)
    [🟦]               (1 one)

Step 4: The Final Answer

After regrouping, we’ve made 50 from the 5 tens and 1 from the leftover one, so:

43 + 8 = 51

This is represented with 5 ten blocks and 1 one block:

    [🟩][🟩][🟩][🟩][🟩]  (5 tens = 50)
    [🟦]               (1 one)

Conclusion

By using blocks and regrouping, we can easily solve addition problems like 43 + 8. We turned 11 ones into a full ten, helping us simplify the problem. Regrouping helps us understand how numbers work together, and it’s a great way to see the process of addition!

A quiz:
1) The blocks show 17 + 5.

	+
17			5